**Superposition Theorem**

The response in any element of linear, bilateral network containing more than one source is the sum of the response produced by the sources each acting independently.

The superposition principle is only applicable to linear networks and systems.

The superposition theorem does not apply to the power as power is proportional to square of the current which is not a linear function.

Steps:-

- Select a single source. Short the other voltage sources and open the current source, if internal impedance's are not known. If known than replace them by their internal impedance.
- Find out the current through or the voltage across the required element, due to the source under consideration.
- Repeat the above step for all the sources.
- Add all the individual effect produced by individual sources to obtain the total current in or voltage across the element.

**Thevenin's Theorem**
Any combination of linear bilateral circuit elements and active sources, regardless of the connection and complexity, connected to a given load Z

_{L }may be replaced by a single two terminal network consisting of a
Single voltage source of V

_{TH }and a single impedance Z_{eq }in the series with the voltage source, across the two terminals of the load Z_{L}.
Steps:-

1. Remove the branch impedance, through which current is required to calculate.

2. Calculate the voltage across the open circuited terminals. This voltage is Thevinin’s equivalent voltage V

_{TH }.
3. Calculate the equivalent impedance Z

_{eq }as viewed through the two terminals of the branch from which current is to be calculated by removing that branch impedance and replacing all the independent sources by their internal impedance.
4. The required current through the branch is given by, I = V

_{TH}/ Z_{L }+ Z_{eq }.

__Norton’s Theorem__

Any combination of linear bilateral circuit elements and active services regardless of the connection or complexity, connected to a given load Z

_{L }can be replaced by a simple two terminal network consisting of a single current source of I_{N }and a single impedance Z_{eq }in parallel with it, across the two terminals of the load Z_{L }.
Steps:-

1. Short the branch through which the current is to be calculated.

2. Find out the current through this short circuited branch. This current is nothing but the Norton’s current I

_{N.}
3. Calculate the equivalent impedance Z

_{eq }as viewed through the two terminals of interest by removing the branch impedance and making all the independent sources inacticve.
4. The current through the branch of interest is I = I

_{N }* Z_{eq}/ Z_{EQ }+ Z_{L}._{ }

Click here for more Electronics and communication engineering questions

## No comments:

## Post a Comment